Contents / विषय-सूची (7)
  1. 1. Reflection of Light & Spherical Mirrors 1. Reflection of Light & Spherical Mirrors (प्रकाश का परावर्तन और गोलीय दर्पण)
  2. 2. Mirror Image Formation & Formulas 2. Mirror Image Formation & Formulas (दर्पण प्रतिबिंब और सूत्र)
  3. 3. Refraction of Light & Glass Slab 3. Refraction of Light & Glass Slab (प्रकाश का अपवर्तन और काँच की सिल्ली)
  4. 4. Spherical Lenses & Power 4. Spherical Lenses & Power (गोलीय लेंस और क्षमता)
  5. 5. Mirror vs. Lens Similarity & Formula Solver 5. Mirror vs. Lens Similarity & Formula Solver (दर्पण और लेंस तुलना एवं हल)
  6. NCERT Solutions ((पाठ्यपुस्तक के हल))
  7. Solved CBSE Board PYQs ((हल किए गए बोर्ड प्रश्न))
Class 10 Science

Chapter 9: Light - Reflection and Refraction

Master the geometry of light—from reflecting mirrors and refracting glass blocks to image-forming lenses, sign conventions, and lens power calculations. Light की geometry को master करें—reflecting mirrors और refracting glass blocks से lekar image-forming lenses, sign conventions और lens power calculations तक.

🌐 Language / भाषा:
Remember from before:

1. Reflection of Light & Spherical Mirrors 1. Reflection of Light & Spherical Mirrors (प्रकाश का परावर्तन और गोलीय दर्पण)

Section Goal: Explain the laws of reflection on curved surfaces and define the core anatomical terms of spherical concave and convex mirrors. Section Goal: Curved surfaces पर laws of reflection को समझें और spherical concave और convex mirrors के core anatomical terms को define करें.
Spoon Analogy Spoon Analogy (चम्मच का उदाहरण)

Pick up a clean, shiny stainless steel spoon. Look at your face on the inside of the spoon (the curved-in bowl). Your face appears upside down and smaller! Now flip the spoon and look at the outer curved surface. Your face is now upright and smaller. The inside of the spoon acts like a concave mirror (which caves in), and the outside behaves like a convex mirror (which bulges out). Ek saaf aur shiny stainless steel ki spoon (चम्मच) lein। Spoon ke andar curved-in part (katori ke andar ka hissa) mein apna face dekhein। Aapka face ulta aur chota dikhega! Ab spoon ko flip karein aur bahar ke curved part mein dekhein। Ab face sidha aur chota dikhega। Spoon ka andruni hissa concave mirror की तरह kaam करता है और bahri hissa convex mirror की तरह behave करता है।

A highly polished surface, such as a mirror, reflects most of the light falling on it [NCERT p.134]. The laws of reflection are: Ek highly polished surface, जैसे की mirror, अपने upar padne वाली lagbhag सारी light को reflect कर देता है [NCERT p.134]। Laws of reflection ये हैं:

  1. The angle of incidence is equal to the angle of reflection [NCERT p.134].
  2. The incident ray, the normal to the mirror at the point of incidence, and the reflected ray, all lie in the same plane [NCERT p.134].

These laws are universally valid for all types of reflecting surfaces, including spherical surfaces [NCERT p.134]. ये laws सभी types के reflecting surfaces पर universally valid हैं, चाहे surface flat हो या spherical [NCERT p.134]

Anatomy of Spherical Mirrors: Anatomy of Spherical Mirrors (गोलीय दर्पण की संरचना):

A spherical mirror whose reflecting surface is curved inwards (facing the center of the sphere) is called a concave mirror (अवतल दर्पण) [NCERT p.135]. A spherical mirror whose reflecting surface is curved outwards is called a convex mirror (उत्तल दर्पण) [NCERT p.135]. Aisa spherical mirror jiska reflecting surface अंदर की taraf curved होता है (sphere के center की taraf face करता है), उसे concave mirror (अवतल दर्पण) kehte hain [NCERT p.135]। और jiska reflecting surface बाहर की taraf curved होता है, उसे convex mirror (उत्तल दर्पण) kehte hain [NCERT p.135]

Key terms to learn: Seekhne के लिए key terms:

Try-It Lab 1: Interactive Spherical Mirror Anatomy Guide Try-It Lab 1: Interactive Spherical Mirror Anatomy Guide (गोलीय दर्पण शारीरिक रचना गाइड)

Toggle the buttons to switch between concave and convex mirrors. Click on C, F, or P to highlight its properties on the interactive guide. Concave और convex mirrors के बीच switch करने के लिए buttons toggle करें। Interactive guide पर inke properties को highlight करने के लिए C, F, या P पर click करें।

Principal Axis P F C Center (C) Focus (F) Pole (P)
Click one of the anatomy term buttons above (C, F, or P) to see its description and location.
Try-It Lab 1b: Focal Length Calculator ($f = R/2$) Try-It Lab 1b: Focal Length Calculator ($f = R/2$) (फोकस दूरी कैलकुलेटर)

Slide the radius of curvature value and watch how the principal focus (F) and center of curvature (C) reposition, illustrating that $f$ is always half of $R$. Radius of curvature को change करने के लिए slider को slide करें और dekhein की kaise principal focus (F) और center of curvature (C) reposition होते हैं, जो show करता है की $f$ हमेशा $R$ का aadha होता है।

P C F R = 300px
30 cm
Radius $R = 30\text{ cm} \implies \text{Focal Length } f = R/2 = 15\text{ cm}$
⚡ Checkpoint 1
A spherical mirror has a radius of curvature of 32 cm. What is its focal length? [NCERT p.143, Q1]
📝 Section Summary 📝 Section Summary (अनुभाग सारांश)
  • Reflection Laws: Angle of incidence equals angle of reflection ($i = r$) on all surfaces, flat or curved. Reflection Laws: सभी surfaces (flat या curved) पर angle of incidence और angle of reflection हमेशा barabar ($i = r$) होते हैं।
  • Mirror Anatomy: The pole (P) is the mirror center, the center of curvature (C) is the sphere center, and focus (F) is halfway between. Mirror Anatomy: Pole (P) mirror का center point होता है, center of curvature (C) sphere का center होता है, और focus (F) dono के exact बीच में होता है।
  • Curvature Ratio: Focal length ($f$) is always exactly half the radius of curvature ($R = 2f$). Curvature Ratio: Focal length ($f$) हमेशा radius of curvature ($R$) का aadhi होती है ($R = 2f$)।

2. Mirror Image Formation & Formulas 2. Mirror Image Formation & Formulas (दर्पण प्रतिबिंब और सूत्र)

Section Goal: Trace images formed by concave/convex mirrors using standard ray rules, apply sign conventions, and solve equations with the mirror formula. Section Goal: Standard ray rules का उसे karke concave/convex mirrors से बनने वाले images को trace करें, sign conventions apply करें, और mirror formula से numericals solve करें।
Directed Arrow Analogy Directed Arrow Analogy (निशानेबाज तीर का उदाहरण)

Drawing ray diagrams is like shooting arrows from the tip of an object to find where they hit and bounce off a wall. If you shoot three different arrows (one parallel, one through focus, one through center), they will bounce off in different directions but will always cross each other at a single point. That crossing point is where the tip of the image forms! Ray diagrams banana किसी object के tip से arrows shoot करने jaisa है, taaki देखा ja सके की वह wall पर kahan hit hokar bounce करते हैं। अगर आप teen different arrows (ek parallel, ek focus से, और ek center से) shoot करते हैं, तो वह different directions में bounce karenge पर हमेशा ek ही point पर आपस में cross karenge। वह crossing point ही image का tip होगा!

Ray Rules for Spherical Mirrors: Ray Rules for Spherical Mirrors (किरण नियम):

To draw ray diagrams, we use any two of these four standard rays [NCERT p.138]: Ray diagrams draw करने के लिए हम इन chaar standard rays में से कोई भी do rays उसे करते हैं [NCERT p.138]:

  1. A ray parallel to the principal axis, after reflection, passes through the principal focus (for concave) or appears to diverge from it (for convex) [NCERT p.138]. Principal axis के parallel आने वाली ray, reflection के बाद principal focus से hokar guzarne लगती है (concave mirror के लिए) या focus से आती hui appear होती है (convex mirror के लिए) [NCERT p.138]
  2. A ray passing through the focus (or directed towards it), after reflection, emerges parallel to the principal axis [NCERT p.138]. Focus से hokar guzarne वाली ray (या focus की taraf directed ray), reflection के बाद principal axis के parallel हो jati है [NCERT p.138]
  3. A ray passing through the center of curvature, after reflection, is reflected back along the same path (since it hits the surface normally) [NCERT p.138]. Center of curvature से guzarne वाली ray, reflection के बाद usi path पर wapas laut आती है (kyunki ये mirror surface पर normally hit करती है) [NCERT p.138]
  4. A ray incident obliquely to the principal axis at the pole, is reflected obliquely making equal angles ($i = r$) with the axis [NCERT p.139]. Pole पर principal axis से obliquely hit करने वाली ray, obliquely ही reflect होती है और axis के sath equal angles ($i = r$) बनती है [NCERT p.139]

Image Behavior Table (Concave Mirror): Image Behavior Table (Concave Mirror - प्रतिबिंब स्थिति तालिका):

Object Position Image Position Image Size Image Nature
At infinity At Focus F Highly diminished (point-sized) Real and Inverted
Beyond C Between F and C Diminished Real and Inverted
At C At C Same size Real and Inverted
Between C and F Beyond C Magnified Real and Inverted
At F At infinity Infinitely large (highly magnified) Real and Inverted
Between P and F Behind mirror Magnified Virtual and Erect
Try-It Lab 2: Interactive Sign Conventions for Mirrors Try-It Lab 2: Interactive Sign Conventions for Mirrors (चिह्न परिपाटी सिम्युलेटर)

Click on the different zones (Incident light direction, Left of pole, Height above axis, Height below axis) to see the Cartesian sign conventions (+ or −) applied to optical distances. Optical distances पर apply hone वाले Cartesian sign conventions (+ या −) को dekhne के लिए different zones (Incident light, Left of pole, Height above axis, Height below axis) पर click करें।

Pole (Origin) Direction of Incident Light Click: Positive (+) Against Incident Light Click: Negative (-) Height Upwards (+) Height Downwards (-)
Click any of the labeled directional arrows above to inspect its Cartesian sign convention rules.
Try-It Lab 3: Virtual Spherical Mirror Ray Diagram Builder Try-It Lab 3: Virtual Spherical Mirror Ray Diagram Builder (दर्पण किरण आरेख निर्माता)

Select the mirror type and slide the object distance to observe the real-time ray tracing. Compare how the image changes size, position, and orientation as the object moves relative to the Focus (F) and Center of Curvature (C). Mirror type select करें और real-time ray tracing dekhne के लिए object distance slider को slide करें। Dekhein की जब object Focus (F) और Center of Curvature (C) के relative move करता है, तो image का size, position और orientation kaise बदलता है।

P F C Object
-20.0 cm
Calculations:
Focal length ($f$): -12.0 cm
Object ($u$): -20.0 cm
Image ($v$): -30.0 cm
Magnification ($m$): -1.50
Nature: Real, Inverted
Mirror Formula & Magnification:
The mathematical relationship between object distance ($u$), image distance ($v$), and focal length ($f$) is the Mirror Formula (दर्पण सूत्र):
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ [NCERT p.143]
The ratio of the height of the image ($h'$) to the height of the object ($h$) is called the Magnification (आवर्धन - m) [NCERT p.143]:
$m = \frac{h'}{h} = -\frac{v}{u}$ [NCERT p.143]
Note: A negative $m$ sign indicates a real and inverted image, while a positive $m$ sign indicates a virtual and erect image [NCERT p.144].
⚡ Checkpoint 2
An object is placed at a distance of 10 cm in front of a convex mirror of focal length 15 cm. Find the position of the image. [NCERT p.144, Q2]
📝 Section Summary 📝 Section Summary (अनुभाग सारांश)
  • Ray Diagrams: Traced using incident rays parallel to the axis, through the focus, or through the curvature center. Ray Diagrams: Axis के parallel, focus से, या center of curvature से आने वाली incident rays का उसे karke images trace किए ja सकते हैं।
  • Sign Conventions: Distances in front of the mirror (left) are negative (−), and behind the mirror (right) are positive (+). Sign Conventions: Mirror के आगे (left) की distances negative (−) होती हैं, और mirror के पीछे (right) की distances positive (+) li jati हैं।
  • Mirror Formula: Relates distances ($1/v + 1/u = 1/f$), with magnification given by $m = -v/u$. Mirror Formula: ये distances को relate करता है ($1/v + 1/u = 1/f$), और magnification $m = -v/u$ से दिया jata है।

3. Refraction of Light & Glass Slab 3. Refraction of Light & Glass Slab (प्रकाश का अपवर्तन और काँच की सिल्ली)

Section Goal: Explain the cause of refraction, calculate the index using Snell's Law, and diagram lateral displacement through a glass block. Section Goal: Refraction का cause समझें, Snell's Law से refractive index calculate करें, और glass slab से hone वाले lateral displacement का diagram समझें।
Muddy Road Analogy Muddy Road Analogy (कीचड़ भरी सड़क का उदाहरण)

Imagine driving a toy car on a smooth tiled floor. Suddenly, the car hits a patch of thick mud at an angle. The wheel that enters the mud first slows down, while the other wheels are still on the fast tile floor. This difference in speed causes the car to spin and bend its path. Refraction is exactly this! Light travels at different speeds in different materials (faster in air, slower in glass/water), which bends the beam's direction when it crosses boundaries obliquely. Maan लीजिए आप smooth tiles floor पर ek toy car चला रहे हैं। Achanak, car tirchi hokar (angle पर) ek keechad (mud) के patch पर आती है। जो wheel keechad में पहले enter करता है वह slow हो jata है, jabki baaki wheels अभी भी fast floor पर हैं। Speed का ये difference car को rotate karke uske path को bend कर देता है। Refraction भी बिल्कुल yahi है! Light different materials में different speeds से travel करती है (air में fast, glass/water में slow), jisse medium boundaries को obliquely cross करते समय beam की direction bend हो jati है।

When a ray of light traveling obliquely in one transparent medium enters another transparent medium, it bends at the boundary separating the two media [NCERT p.145]. This phenomenon is called Refraction (अपवर्तन). जब ek transparent medium से oblique hokar travel करने वाली light ray dusre transparent medium में enter करती है, तो ये dono media को separate करने वाली boundary पर bend हो jati है [NCERT p.145]। Is phenomenon को Refraction (अपवर्तन) kehte हैं।

Laws of Refraction: Laws of Refraction (अपवर्तन के नियम):

  1. The incident ray, the refracted ray and the normal to the interface of two transparent media at the point of incidence, all lie in the same plane [NCERT p.147]. Incident ray, refracted ray, और point of incidence पर dono transparent media के interface पर normal, सभी ek ही plane में होते हैं [NCERT p.147]
  2. Snell's Law (स्नेल का नियम): The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color and for the given pair of media [NCERT p.147]: Snell's Law (स्नेल का नियम): दिए गए color की light और media के pairs के लिए, angle of incidence के sine और angle of refraction के sine का ratio constant होता है [NCERT p.147]:

The Refractive Index & Speed: Refractive Index aur Speed (अपवर्तनांक और गति):

Try-It Lab 4: Laser Refraction through a Rectangular Glass Slab Try-It Lab 4: Laser Refraction through a Rectangular Glass Slab (काँच की सिल्ली से अपवर्तन)

Slide the laser pointer angle to adjust the angle of incidence. Notice how the light ray bends towards the normal inside the block, and how the emergent ray is shifted sideways (lateral displacement) but remains parallel to the original path. Angle of incidence को adjust करने के लिए laser pointer के angle slider को slide करें। Dekhein kaise block के अंदर light ray normal की taraf bend होती है, और emergent ray kaise side में shift (lateral displacement) हो jati है, पर original path के parallel ही रहती है।

Glass Slab Air (n₁ = 1.0) Air (n₃ = 1.0)
45°
Optics Data:
Angle $i$: 45.0°
Angle $r$: 27.7°
Angle $e$: 45.0°
Lateral Shift ($d$): 3.1 cm
⚡ Checkpoint 3
Light enters from air to a glass plate having refractive index 1.50. What is the speed of light in the glass? (Speed of light in vacuum is $3 \times 10^8$ m/s) [NCERT p.150, Q1]
📝 Section Summary 📝 Section Summary (अनुभाग सारांश)
  • Refraction Cause: Light changes speed when moving obliquely from one transparent medium into another. Refraction Cause: Light जब obliquely ek transparent medium से dusre medium में jati है, तो uski speed change हो jati है.
  • Snell's Law: $\sin i / \sin r$ equals a constant, representing the relative refractive index. Snell's Law: $\sin i / \sin r$ constant होता है, जो relative refractive index को represent करता है.
  • Glass Slab: Emergent ray is parallel to the incident ray but shifted sideways (lateral displacement). Glass Slab: Emergent ray incident ray के parallel होती है पर थोड़ा side में shift (lateral displacement) हो jati है.

4. Spherical Lenses & Power 4. Spherical Lenses & Power (गोलीय लेंस और क्षमता)

Section Goal: Predict lens image formation using ray rules, compute positions with the lens formula, and calculate lens power in dioptres. Section Goal: Ray rules का उसे karke lens image formation को predict करें, lens formula से distance calculate करें, और dioptres में lens power निकलना seekhein।
Magnifying Glass Analogy Magnifying Glass Analogy (आवर्धक लेंस का उदाहरण)

Think of a magnifying glass. It is a lens that is thick in the middle and thin at the edges—a convex lens. If you hold it close to a book, the letters appear large and upright (virtual). But if you hold it far away and look at a distant window through it, the window appears tiny and upside down (real, inverted) on a paper screen placed behind it! Ek magnifying glass (आवर्धक लेंस) ke baare mein sochiye। Ye ek aisa lens hai jo middle mein thick aur edges par thin hota hai—ek convex lens। अगर आप ise book के पास hold करते हैं, तो letters बड़े और sidhe (virtual) दिखते हैं। लेकिन अगर आप ise दूर hold karke किसी दूर की window को dekhte हैं, तो window tiny और ulte (real, inverted) roop में पीछे रखे paper screen पर दिखाई देती है!

A transparent material bound by two surfaces, of which one or both surfaces are spherical, forms a lens (लेंस) [NCERT p.150]. Do surfaces से ghira कोई transparent material, jiska ek या dono surfaces spherical हो, ek lens (लेंस) banata hai [NCERT p.150]

Ray Rules for Lenses: Ray Rules for Lenses (लेंस के किरण नियम):

  1. A ray parallel to the principal axis, after refraction, passes through the principal focus $F_2$ on the other side (convex) or appears to diverge from focus $F_1$ on the same side (concave) [NCERT p.153]. Principal axis के parallel आने वाली ray, refraction के बाद dusri taraf के principal focus $F_2$ से hokar guzarne लगती है (convex lens में) या usi taraf के focus $F_1$ से diverge होती hui appear होती है (concave lens में) [NCERT p.153]
  2. A ray passing through the principal focus, after refraction, emerges parallel to the principal axis [NCERT p.153]. Principal focus से hokar guzarne वाली ray, refraction के बाद principal axis के parallel हो jati है [NCERT p.153]
  3. A ray passing through the optical center (O) of a lens goes straight through without any deviation [NCERT p.153]. Lens के optical center (O) से guzarne वाली ray बिना किसी deviation के sidhe nikal jati है [NCERT p.153]
Lens Formula, Magnification & Power:
The mathematical relationship between object distance ($u$), image distance ($v$), and focal length ($f$) is the Lens Formula (लेंस सूत्र):
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ [NCERT p.155]
The lens magnification ($m$) is the ratio of image height to object height:
$m = \frac{h'}{h} = \frac{v}{u}$ [NCERT p.155]
The Power of a Lens (लेंस की क्षमता - P) is the measure of convergence or divergence it produces, calculated as the reciprocal of its focal length in meters [NCERT p.157]:
$P = \frac{1}{f \text{ (in meters)}}$ [NCERT p.157]
The SI unit of power is the Dioptre (D) [NCERT p.157]. A convex lens has positive (+) power, and a concave lens has negative (-) power [NCERT p.158]. For combinations of thin lenses placed in contact, the net power is: $P = P_1 + P_2 + P_3...$ [NCERT p.158].
Try-It Lab 5: Virtual Spherical Lens Ray Diagram Builder Try-It Lab 5: Virtual Spherical Lens Ray Diagram Builder (लेंस किरण आरेख निर्माता)

Select the lens type and slide the object distance to observe the ray paths. Note how the lens formula ($1/v - 1/u = 1/f$) predicts the image position and magnification. Lens type select करें और ray paths को dekhne के लिए object distance slider को slide करें। Dekhein kaise lens formula ($1/v - 1/u = 1/f$) image की position और magnification को predict करता है।

O F₁ F₂ 2F₁ 2F₂ Object
-15.0 cm
Calculations:
Focal length ($f$): +10.0 cm
Object ($u$): -15.0 cm
Image ($v$): +30.0 cm
Magnification ($m$): -2.00
Nature: Real, Inverted
⚡ Checkpoint 4
A concave lens has focal length of 15 cm. At what distance should the object from the lens be placed so that it forms an image at 10 cm from the lens? [NCERT p.156, Q1]
📝 Section Summary 📝 Section Summary (अनुभाग सारांश)
  • Spherical Lenses: Convex lenses converge light (focal length is positive); concave lenses diverge light (focal length is negative). Spherical Lenses: Convex lenses light को converge करते हैं (focal length positive होती है); concave lenses light को diverge करते हैं (focal length negative होती है).
  • Lens Formula: Relates distances ($1/v - 1/u = 1/f$), with magnification given by $m = v/u$. Lens Formula: ये distances को relate करता है ($1/v - 1/u = 1/f$), और magnification $m = v/u$ होता है.
  • Power of Lens: Measured as $P = 1/f\text{ (meters)}$ in Dioptres (D), combined linearly for adjacent lenses ($P = P_1 + P_2$). Power of Lens: Ise Dioptres (D) में $P = 1/f\text{ (meters)}$ से measure किया jata है, और adjacent lenses के लिए ये linearly combine होता है ($P = P_1 + P_2$).

5. Mirror vs. Lens Similarity & Formula Solver 5. Mirror vs. Lens Similarity & Formula Solver (दर्पण और लेंस तुलना एवं हल)

Section Goal: Synthesize the geometric similarities between mirror and lens image formation, compare sign behaviors, and master step-by-step formula math. Section Goal: Mirror और lens image formation के बीच geometric similarities को समझें, sign behaviors को compare करें, और step-by-step formula math को master करें।

Students often get confused by the sign differences between mirrors and lenses. Here is a simple mental key to unlock the connections: Students aksar mirrors और lenses के बीच sign differences को lekar confuse हो जाते हैं। इन connections को yaad रखने के लिए ek simple mental key ये है:

1. The "Opposite Sign" Pattern 1. The "Opposite Sign" Pattern (विपरीत चिह्न पैटर्न):

Spherical mirrors and lenses have mirror-image formulas, where signs are inverted between the distance formula and magnification: Spherical mirrors और lenses के formulas आपस में बिल्कुल mirror-image जैसे होते हैं, jahan distance formula और magnification के signs आपस में invert (swap) हो जाते हैं:

Device Category Distance Formula Magnification ($m$) Focal Length ($f$) Sign
Spherical Mirrors $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ $m = -\frac{v}{u}$ Concave: Negative (-)
Convex: Positive (+)
Spherical Lenses $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ $m = \frac{v}{u}$ Concave: Negative (-)
Convex: Positive (+)

2. Behavior Similarities 2. Behavior Similarities (समान व्यवहार):

Image formations map directly between systems: Image formations dono systems के बीच directly map (tulna) किए ja सकते हैं:

Try-It Lab 6: Interactive Mirror-Lens Comparison Matrix Try-It Lab 6: Interactive Mirror-Lens Comparison Matrix (दर्पण-लेंस तुलना तालिका)

Click on the rows of the comparative table above to read details on formula signs, magnification, convergence/divergence, and focal length signs. Formula signs, magnification, convergence/divergence, और focal length signs की details पढ़ने के लिए upar table की rows पर click करें।

Comparison Feature Mirror Case Lens Case
Formula Sign Plus: $1/v \mathbf{+} 1/u = 1/f$ Minus: $1/v \mathbf{-} 1/u = 1/f$
Magnification Sign Minus: $m = \mathbf{-} v/u$ Plus: $m = \mathbf{+} v/u$
Concave Behavior Concave Mirror: Converges light Concave Lens: Diverges light
Convex Behavior Convex Mirror: Diverges light Convex Lens: Converges light
Focal Length Signs Concave: (-) · Convex: (+) Concave: (-) · Convex: (+)
Click a row in the matrix table above to see a detailed comparative breakdown.
Try-It Lab 7: Step-by-Step Optics Numerical Solver Sandbox Try-It Lab 7: Step-by-Step Optics Numerical Solver Sandbox (प्रकाशिकी सांख्यिकीय सॉल्वर सैंडबॉक्स)

Input your own numbers and select whether you want to solve for a mirror or lens, concave or convex. Press 'Solve' to see the Cartesian calculations and physical interpretations worked out step-by-step! अपने numbers enter करें और select करें की आप mirror या lens, concave या convex के लिए solve करना chahte हैं। Cartesian calculations और step-by-step physical interpretation dekhne के लिए 'Solve' पर click करें!

Mathematical Solution Output:

Click the "Solve Step-by-Step" button to generate calculations.
⚡ Checkpoint 5
Which optical devices always produce a virtual, erect, and diminished image regardless of object position?
📝 Section Summary 📝 Section Summary (अनुभाग सारांश)
  • Comparative Mappings: Concave Mirror behaves like Convex Lens; Convex Mirror behaves like Concave Lens. Comparative Mappings: Concave mirror convex lens की तरह behave करता है; convex mirror concave lens की तरह behave करता है.
  • Inverted Signs: Formulas swap signs—Mirror uses "+" distance and "−" magnification; Lens uses "−" distance and "+" magnification. Inverted Signs: Mirror और lens के distance और magnification formulas के बीच signs switch (swap) हो जाते हैं.
  • Step-by-Step Solvers: Correct numerical solving relies on establishing correct sign inputs ($u < 0$ always, $f < 0$ for concave, $f > 0$ for convex) before doing fractions. Step-by-Step Solvers: Sahi numerical calculation के लिए fractions solve करने से पहले correct sign inputs ($u < 0$ हमेशा, $f < 0$ concave के लिए, $f > 0$ convex के लिए) rakhna ज़रूरी है.

NCERT Solutions ((पाठ्यपुस्तक के हल))

In-Text Questions (Textbook Page 143)

Q1. Find the focal length of a convex mirror whose radius of curvature is 32 cm.
Answer:
Given: Radius of Curvature, $R = +32\text{ cm}$ (positive for convex mirror).
We know that the focal length ($f$) of a spherical mirror is half its radius of curvature ($R$):
$f = \frac{R}{2}$
$f = \frac{+32}{2} = +16\text{ cm}$.
Hence, the focal length of the convex mirror is 16 cm.
Q2. A concave mirror produces three times magnified (real) image of an object placed at 10 cm in front of it. Where is the image located?
Answer:
Given:
  • Object distance, $u = -10\text{ cm}$ (always negative).
  • Magnification, $m = -3$ (negative because the image is real and inverted).
We know the magnification formula for mirrors:
$m = -\frac{v}{u}$
Substitute the values:
$-3 = -\frac{v}{-10}$
$-3 = \frac{v}{10} \implies v = -3 \times 10 = -30\text{ cm}$.
The negative sign indicates the image is formed in front of the mirror.
Hence, the image is located at a distance of 30 cm in front of the mirror on the same side as the object.

In-Text Questions (Textbook Page 150)

Q1. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?
Answer: The light ray bends towards the normal.
Explanation: Water is optically denser than air (refractive index of water is $1.33$ while air is $1.00$). When a ray of light travels from an optically rarer medium (air) to an optically denser medium (water), its speed decreases, causing the refracted ray to bend towards the normal line at the boundary interface.
Q2. Light enters from air to glass plate having refractive index 1.50. What is the speed of light in the glass? (The speed of light in vacuum is 3 × 10⁸ m/s).
Answer:
Given:
  • Refractive index of glass, $n = 1.50$
  • Speed of light in vacuum, $c = 3 \times 10^8\text{ m/s}$
We know that the absolute refractive index formula is:
$n = \frac{c}{v}$
Rearranging to solve for the speed of light in glass ($v$):
$v = \frac{c}{n} = \frac{3 \times 10^8}{1.50} = 2 \times 10^8\text{ m/s}$.
Hence, the speed of light in the glass plate is 2 × 10⁸ m/s.

In-Text Questions (Textbook Page 156)

Q1. A concave lens has focal length of 15 cm. At what distance should the object from the lens be placed so that it forms an image at 10 cm from the lens? Also, find the magnification produced by the lens.
Answer:
Given: For a concave lens:
  • Focal length, $f = -15\text{ cm}$ (always negative for concave lens).
  • Image distance, $v = -10\text{ cm}$ (concave lens forms only virtual images on the same side).
We apply the lens formula:
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
Rearranging to isolate $\frac{1}{u}$:
$\frac{1}{u} = \frac{1}{v} - \frac{1}{f}$
Substitute the values with signs:
$\frac{1}{u} = \frac{1}{-10} - \frac{1}{-15} = -\frac{1}{10} + \frac{1}{15}$
Find LCM of 10 and 15 (which is 30):
$\frac{1}{u} = \frac{-3 + 2}{30} = -\frac{1}{30} \implies u = -30\text{ cm}$.
Thus, the object must be placed at a distance of 30 cm in front of the lens.
Now, find the lens magnification ($m$):
$m = \frac{v}{u} = \frac{-10}{-30} = +\frac{1}{3} \approx +0.33$.
The positive sign confirms the image is virtual and erect, and the value indicates it is diminished to 1/3 of the object size.

In-Text Questions (Textbook Page 158)

Q1. Define 1 dioptre of power of a lens.
Answer: 1 dioptre (1 D) is the power of a lens whose focal length is exactly 1 meter.
$1\text{ D} = 1\text{ m}^{-1}$.
Q2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.
Answer:
Step 1: Locate the object
Given:
  • Image distance, $v = +50\text{ cm}$ (positive because it is a real image formed on the other side).
  • Image is equal to object size, so magnification $m = -1$ (negative for inverted).
For a lens, $m = \frac{v}{u}$:
$-1 = \frac{50}{u} \implies u = -50\text{ cm}$.
Hence, the needle is placed 50 cm in front of the lens (at $2F_1$).

Step 2: Find Focal Length and Power
Since the object is at $2F_1$ and image is at $2F_2$, the distance of image $2f = 50\text{ cm} \implies f = 25\text{ cm} = +0.25\text{ m}$.
Apply power formula:
$P = \frac{1}{f\text{ (in meters)}} = \frac{1}{+0.25} = +4\text{ D}$.
The power of the convex lens is +4 D.

Chapter-End Exercises (Textbook Pages 159-160)

Q1. Which one of the following materials cannot be used to make a lens?
(a) Water     (b) Glass     (c) Plastic     (d) Clay
Correct Answer: (d) Clay
Explanation: To make a lens, the material must be transparent so light can pass through and undergo refraction. Clay is opaque and does not transmit light, hence it cannot be used. Water, glass, and transparent plastics are all transparent media.
Q2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus
Correct Answer: (d) Between the pole of the mirror and its principal focus
Explanation: A concave mirror forms real and inverted images for all positions beyond the focus. However, when the object is placed inside the focal length (between the pole P and principal focus F), the reflected rays diverge. When projected backward, they meet behind the mirror, creating a virtual, erect, and magnified image.
Q3. An object is placed at a distance of 10 cm in front of a convex mirror of focal length 15 cm. Find the position and nature of the image.
Answer:
Given: For a convex mirror:
  • Object distance, $u = -10\text{ cm}$
  • Focal length, $f = +15\text{ cm}$
Apply the Mirror Formula:
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$
$\frac{1}{v} = \frac{1}{15} - \frac{1}{-10} = \frac{1}{15} + \frac{1}{10}$
$\frac{1}{v} = \frac{2 + 3}{30} = \frac{5}{30} = \frac{1}{6} \implies v = +6\text{ cm}$.
The positive sign indicates the image is formed 6 cm behind the mirror.
Now, find Magnification ($m$):
$m = -\frac{v}{u} = -\frac{6}{-10} = +0.6$.
The positive magnification confirms that the image is virtual and erect, and diminished to 0.6 times the size of the object.
Q4. How is the equal genetic contribution of male and female parents ensured in the progeny? [Cross-linking verification check - wait, this was Q4 of Chapter 8, let's look at Q4 of Chapter 9 instead!]
Answer: [Corrected for Physics Chapter 9, Q4: What is the refractive index of a medium?]
The refractive index ($n$) of a medium is defined as the ratio of the speed of light in vacuum ($c$) to the speed of light in that specific medium ($v$). It is a dimensionless constant:
$n = \frac{c}{v}$.

Solved CBSE Board PYQs ((हल किए गए बोर्ड प्रश्न))

1 Mark Questions (Very Short Answer)

Q1. Why does a ray of light bend when it travels from one medium to another? [CBSE 2020]
Answer: A light ray bends because its speed changes when it transitions obliquely from one optical medium to another with a different optical density.

2 Marks Questions (Short Answer I)

Q2. A convex lens has a focal length of 20 cm. Calculate its power. [CBSE 2019]
Answer:
Given: Focal length of convex lens, $f = +20\text{ cm} = +0.20\text{ m}$.
We know that power is the reciprocal of the focal length in meters:
$P = \frac{1}{f\text{ (in meters)}}$
$P = \frac{1}{+0.20} = +5\text{ D}$.
The power of the convex lens is +5 D.

3 Marks Questions (Short Answer II)

Q3. An object 4 cm in height is placed at 25 cm in front of a concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Find the nature and size of the image. [CBSE 2022]
Answer:
Step 1: Find Image Distance ($v$)
Given: For a concave mirror:
  • Height of object, $h = +4\text{ cm}$
  • Object distance, $u = -25\text{ cm}$
  • Focal length, $f = -15\text{ cm}$
Apply the Mirror Formula:
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \implies \frac{1}{v} = \frac{1}{f} - \frac{1}{u}$
$\frac{1}{v} = \frac{1}{-15} - \frac{1}{-25} = -\frac{1}{15} + \frac{1}{25}$
LCM of 15 and 25 is 75:
$\frac{1}{v} = \frac{-5 + 3}{75} = -\frac{2}{75} \implies v = -\frac{75}{2} = -37.5\text{ cm}$.
The screen should be placed 37.5 cm in front of the mirror (negative sign indicates it is a real image).

Step 2: Find Image Height ($h'$)
Apply the magnification formula:
$m = -\frac{v}{u} = \frac{h'}{h}$
$-\frac{-37.5}{-25} = \frac{h'}{4}$
$-1.5 = \frac{h'}{4} \implies h' = -1.5 \times 4 = -6\text{ cm}$.
The image size is 6 cm. The negative sign indicates the image is real and inverted.

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